The Barclays ATP World Tour Finals has a round-robin format, with eight players/teams divided into two groups of four. The eight seeds are determined by the Emirates ATP Rankings and Emirates ATP Doubles Team Rankings on the Monday after the last ATP World Tour tournament of the calendar year. All singles matches are the best of three tie-break sets, including the final. All doubles matches are two sets (no ad) and a Match Tie-break.
The top seeded players/team is placed in Group A and the second seeded player/team is placed in Group B. Players/teams seeded 3 and 4, 5 and 6, 7 and 8, are then drawn in pairs with the first drawn placed in Group A. Each player/team plays the three other players/teams in his group. The winner of each group (best overall record) is placed in separate semi-final brackets, with the top player/team in Group A playing the runner-up in Group B, and vice versa. If two or more players/teams are tied after the round robin matches, the ties are broken by the Tie-Break Procedure.
The launch of the Finals Club in 2015 was highlighted by the renaming of Groups A and B for both the singles and doubles in honour of players that made an indelible mark on the tournament in the 1970s.
- Group A was renamed in honour of Stan Smith, winner of the inaugural tournament in Tokyo in 1970.
- Group B was renamed in honour of Ilie Nastase, a four-time winner of the event from 1971-1973 and '75.
- Group A was renamed Ashe/Smith, in honour of Arthur Ashe & Stan Smith, winners of the inaugural tournament in Tokyo in 1970.
- Group B was renamed Fleming/McEnroe, in honour of Peter Fleming & John McEnroe, seven-time consecutive winners of the tournament..
Semi-final Qualifying ProcedureThe final standings of each group is determined by the first of the following methods that apply:
a) Greatest number of wins;
b) Greatest number of matches played;
Comment: 2-1 won-loss record beats a 2-0 won-loss record; a 1-2 record beats a 1-0 record.
c) Head-to-head results if only two (2) players are tied,
d) If three (3) players are tied, then...